Edin Dzeko made the switch to AS Roma in 2016, moving from Manchester City.
The Serie A outfit are believed to have paid around £10m for Dzeko, and given how well he has performed over the last several seasons, that appears to have been a bit of a steal.
In total, Dzeko has featured 198 times across all competitions for Roma.
In those 198 ties, the experienced forward has found the back of the net 95 times, and also provided 40 assists.
Dzeko has also hit the ground running in the 2019/20 campaign, scoring six and assisting two in 15 Serie A outings for Roma.
View this post on Instagram
Dzeko set for Premier League return?
But could we see the former Manchester City man back in the Premier League in the near future?
Dzeko is currently contracted to Roma until July of 2022.
But according to the Mirror, Tottenham boss Jose Mourinho is keen to bring in Dzeko in January, to provide cover for Harry Kane.
After Fernando Llorente left the Lilywhites this past summer, Spurs have very little cover for Kane at striker.
Yes, both Lucas and Heung-Min Son can play in said role, but that is not their natural position.
So, Spurs’ reported interested in Dzeko does make sense, with the aforementioned report from the Mirror also claiming that Mourinho sent one of his senior scouts to Italy last week in order to scout Dzeko.
But would Dzeko actually be willing to make the switch to north London?
The 33-year-old is a regular starter in Rome. But given his age and the ability of Harry Kane, it is hard to see Dzeko garnering much game time, should he sign for Tottenham.
|Game||Time||Prediction/Live Score||How to Watch|
|Manchester United FC vs LASK||5 August, 20:00 (In 8 hours)||3-0||📺|
|FC Inter Milano vs Getafe CF||5 August, 20:00 (In 8 hours)||2-1||📺|
|FC Copenhagen vs Istanbul Basaksehir FK||5 August, 17:55 (In 6 hours)||1-1||📺|
|FC Shakhtar Donetsk vs VfL Wolfsburg||5 August, 17:55 (In 6 hours)||2-1||📺|
101 Great Goals provides ways to watch and bet on football matches. Purchases you make through our links may earn us a commission.